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Top Questions
Why do function pointer definitions work with any number of ampersands '&' or asterisks '*'?
243 votes
5 answers
Doesn't putting a "virtual destructor inside an interface" make it, by definition, not an interface anymore?
26 votes
4 answers
Why doesn't deleting my pointer delete my pointer?
16 votes
8 answers
When Declaring a Reference to an Array of Ints, why must it be a reference to a const-pointer?
15 votes
7 answers
Once an array-of-T has decayed into a pointer-to-T, can it ever be made into an array-of-T again?
14 votes
3 answers