Preg replace till dot including that

user_18261729 0
Viewed 36

I am having one line I have to replace that below is the line

/myhome/ishere/where/are.you.ha

Here I have a live regex

preg_match('/(.+\/)[^.]+(.+\.ha)/', $input_line, $output_array);

it results me live this

/myhome/ishere/where/.you.ha

But I need a answer like this

/myhome/ishere/where/you.ha

Please anyone help me to remove this dot.

preg-match preg-replace php regex
3 Answers

You can use

/^(.+\/)[^.]*\.(.*\.ha)$/

See the regex demo. Details:

  • ^ - start of a string
  • (.+\/) - Group 1: any one or more chars other than line break chars as many as possible and then /
  • [^.]* - zero or more chars other than a .
  • \. - a . char
  • (.*\.ha) - Group 2: any zero or more chars other than line break chars as many as possible and then .ha
  • $ - end of a string
user_38329700

You could write the pattern as this, which will give you 2 capture groups that you can use:

(.+\/)[^.]+\.([^.]+\.ha)$

Explanation

  • (.+\/) Capture group 1, match 1+ chars and then the last /
  • [^.]+ Match 1+ non dots
  • \. Match a dot
  • ([^.]+\.ha) Match non dots, then .ha
  • $ End of string

Regex demo | Php demo

If you use $1$2 in the replacement:

$pattern = "/(.+\/)[^.]+\.([^.]+\.ha)$/";
$s = "/myhome/ishere/where/are.you.ha";
echo preg_replace($pattern, "$1$2", $s);

Output

/myhome/ishere/where/you.ha

Or see a code an example using preg_match with 2 capture groups.

user_54249880

Although I got the answer I was mistaking to put +\. in between

(.+/)[^.]+\.(.+\.ha)

preg_replace('/(.+\/)[^.]+\.(.+\.ha)/', '$1$2', $input_lines);

This is how it works.

user_182617290
Related