Python Regex to find if a given string follows a continuous pattern of alternate vowel,consonant or consonant,vowel

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I need to check if a string is formed by the continuous pattern of alternating vowels and consonants and vice versa is a valid pattern string or not..,here is my code

import re
s1="japan"
s2="iran"
s3="brazil"

pattern=re.compile(r'^(([aeiou][^aeiou])+|([^aeiou][aeiou])+)$')
matching1=re.match(pattern,s1)
matching2=re.match(pattern,s2)
matching3=re.match(pattern,s3)
if(matching1):
    print(f"{s1} follows a valid pattern")
else:
    print(f"{s1} does not follows a valid pattern")

so, what i am trying to do is, i need to return string s1 as a valid pattern string,because Jis a consonant , A is a vowel , P is a consonant,A is a vowel ,N is a consonant

and similarly; s2 as a valid pattern string and s3 as an invalid pattern string.

but what i got is, S1 and S3 as an invalid pattern string

and s2 as a valid pattern string and that too failed if i put another vowel lets say A and make it as irana

string-matching python-3.x regex string
2 Answers

Your regexp only matches if there are an even number of characters. The alternative that's vowel-consonant needs to allow an optional vowel at the end, and vice versa for the other alternative.

pattern=re.compile(r'^(([aeiou][^aeiou])+[aeiou]?|([^aeiou][aeiou])+[^aeiou]?)$')

DEMO

user_14918950

An alternative, search for two consecutive consonants/vowels:

import re

test_cases = ["japan", "iran", "brazil"]

pat = re.compile(r"[aeiou]{2,}|[^aeiou]{2,}")

for t in test_cases:
    if pat.search(t):
        print(f"{t} does not follows a valid pattern")
    else:
        print(f"{t} follows a valid pattern")

Prints:

japan follows a valid pattern
iran follows a valid pattern
brazil does not follows a valid pattern
user_100359850
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