Sort of an OR operation on two strings in python

user_3217310 0
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I have two strings:

StringA = "SushantSingh"
StringB = "SinghRajput"

Desired resultant string is:

result = "SushantSinghRajput"

How to get the result string using some operations in python from StringA and StringB? A good/clean way. Basically sort of an OR Operation.

My attempt for others to view:

import difflib
StringA = "SushantSingh"
StringB = "SinghRajput"
res = ""
res_S = ""
res = [li[2] for li in difflib.ndiff(StringA,StringB)]
for ele in res:
    res_S+=ele
print(res_S)

Out: 'SushantSinghRajput'

but I seek even less lines answer. more short version is:

import difflib
StringA = "SushantSingh"
StringB = "SinghRajput"
res = ''.join([li[2] for li in difflib.ndiff(StringA,StringB)])
print(res)

any other better way without using difflib ?

python-3.x list python string
2 Answers

A simple way to do that would be using startsWith and iterating over one string:

StringA = "SushantSingh"
StringB = "SinghRajput"

merged = ""

for index in range(len(StringA)):
    if StringB.startswith(StringA[index:]):
        merged = StringA[:index] + StringB
        break
else:
    merged = StringA + StringB

print(merged)

But it is obviously not a one liner, if this was your requirement ...

user_100341770

@Sami Tahri answer is good but I think it is better if you start from the end of of StringA is more efficient.

StringA = "SushantSingh"
StringB = "SinghRajput"

merged = ""
for i in range(len(StringA)-1, -1, -1):
    if StringB.startswith(StringA[i:]):
        merged = StringA[:i]+StringB
        break
else:
    merged = StringA+StringB
print(merged)
user_169669450
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