How to capture a sentence but ignore whitespace more than 1 with regex?

user_13285583 0
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My goal is to capture this string.

      04/07          TRSF E-BANKING DB                0207/QEZDF/WSA2321                                           500.00 DB
                     TANGGAL :02/07                   Q0344XXXXX12
                                                      SALZXA YAEAS SAX

What I've tried:

  1. The regex used: (\d{2}/\d{2})([ ]{1,}[\w -]*)

However, the [\w -]* capture TRSF E-BANKING DB instead of just the TRSF E-BANKING DB.

I am not sure how to tell the regex within the match case that the whitespace length should not be more than 1.

regex
1 Answers

You can write the pattern as:

(\d{2}\/\d{2}) +([\w-]+(?: [\w-]+)*)

Explanation

  • (\d{2}\/\d{2}) Capture group 1, match 2 digits, / and 2 digits
  • + Match 1 or more spaces
  • ( Capture group 2
    • [\w-]+ Match 1+ word chars or -
    • (?: [\w-]+)* Optionally repeat matching 1 space and 1 or more word chars or -
  • ) Close group 2

Regex demo

user_54249880
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