why it's works when I use a integer index but don't whit a i itterable variable inside a loop in Django template engine

user_19371185 0
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this is gives a none values :

   {%for i in l%}
<tr>

  <td>{{con.hotel.i}}</td>
</tr>
{%endfor%}

while this works and give the correct values

  {%for i in l%}
<tr>
  <td>{{con.hotel1.0}}</td>
</tr>
{%endfor%}
jinja2 django html python loops
1 Answers

Because it then will try to access the .i attribute. If you write .item, then it will first try to access .item, then ['item'] and finally try [int('item')], so for .0 that means it tries .0 which fails, ['0'] which fails as well, and then [int('0')], which will use the first item.

For hotel.i, it will thus first try hotel.i, then hotel['i'], and finally try to convert 'i' to an int, which will all fail.

It would be confusing to also try [item], since that would be confusing in case .item as attribute exists.

For jinja however, you can subscript, so:

{% for i in l %}
  <tr>
    <td>{{ con.hotel[i] }}</td>
  </tr>
{% endfor %}
user_675790
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