If you don't use exact maximum and minimum, but 1st and 99th percentile, or something nearby (0.1%?), you'll get some nicer contrast. It'll cut away outliers due to noise, compression, etc.
Additionally, you should want to mess with gamma, or scale the values linearly, to achieve white balance.
I'll apply a "gray world assumption" and scale each plane so the mean is gray. I'll also mess with gamma, but that's just messing around.
And... all of that completely ignores gamma mapping, both of the "negative" and of the outputs.
import numpy as np
import cv2 as cv
import skimage
im = cv.imread("negative.png")
(bneg,gneg,rneg) = cv.split(im)
def stretch(plane):
# take 1st and 99th percentile
imin = np.percentile(plane, 1)
imax = np.percentile(plane, 99)
# stretch the image
plane = (plane - imin) / (imax - imin)
return plane
b = 1 - stretch(bneg)
g = 1 - stretch(gneg)
r = 1 - stretch(rneg)
bgr = cv.merge([b,g,r])
cv.imwrite("positive.png", bgr * 255)

b = 1 - stretch(bneg)
g = 1 - stretch(gneg)
r = 1 - stretch(rneg)
# gray world
b *= 0.5 / b.mean()
g *= 0.5 / g.mean()
r *= 0.5 / r.mean()
bgr = cv.merge([b,g,r])
cv.imwrite("positive_grayworld.png", bgr * 255)

b = 1 - np.clip(stretch(bneg), 0, 1)
g = 1 - np.clip(stretch(gneg), 0, 1)
r = 1 - np.clip(stretch(rneg), 0, 1)
# goes in the right direction
b = skimage.exposure.adjust_gamma(b, gamma=b.mean()/0.5)
g = skimage.exposure.adjust_gamma(g, gamma=g.mean()/0.5)
r = skimage.exposure.adjust_gamma(r, gamma=r.mean()/0.5)
bgr = cv.merge([b,g,r])
cv.imwrite("positive_gamma.png", bgr * 255)

Here's what happens when gamma is applied to the inverted picture... a reasonably tolerable transfer function results from applying the same factor twice, instead of applying its inverse.


Trying to "undo" the gamma while ignoring that the values were inverted... causes serious distortions:


And the min/max values for contrast stretching also affect the whole thing.
A simple photo of a negative simply won't do. It'll include stray light that offsets the black point, at the very least. You need a proper scan of the negative.