Why does doubling just puts the number twice?

user_19754254 0
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So I'm real new to Ruby and I'm not sure exactly how things work. I've been working through the Codecademy and experimenting with some things. Anyway, I want to use a yield statement to double a number I feed into the terminal. Here's what I have

 def double(i)
  puts "Type a number!"
  yield(i)
  puts "Look at that! It's doubled!"
end

double(gets.chomp) {|i| puts i*2}

Weirdly, rather than doubling it, this is returning the number twice, i.e. if I input 3, I get 33, not 6. When I replace the gets.chomp with an integer, it doubles it properly though, so Somehow my gets.chomp must be flawed, but I have no idea how. Any advice would help immensely. Thanks!

ruby
1 Answers

Try using the .to_i function since gets.chomp returns text.

 def double(i)
  i = i.to_i
  puts "Type a number!"
  yield(i)
  puts "Look at that! It's doubled!"
end

double(gets.chomp) {|i| puts i*2}

tried and tested in codecademy

user_188435850
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