How to create rrule occurrence for even weeks

user_252194 0
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I am using rrule from python-dateutil 2.8.2 in python 3.10 to generate datetimes.

I can't figure out how to create a rrule that creates outputs for only even week numbers.

It seems like the "byweekno" parameter might be able to do this, but I haven't been able to find any examples that explain how to only output from even weeks.

Edit 1: Unfortunately there is no guarantee that my "dtstart" is in an even week, which means that using "interval" would not be helpful as far as I can tell.

rrule week-number python-dateutil python-3.x datetime
2 Answers

This construct should work:

In [23]: list(rrule(freq=WEEKLY, interval=2, count=5))
Out[23]: 
[datetime.datetime(2022, 8, 6, 15, 45, 35),
 datetime.datetime(2022, 8, 20, 15, 45, 35),
 datetime.datetime(2022, 9, 3, 15, 45, 35),
 datetime.datetime(2022, 9, 17, 15, 45, 35),
 datetime.datetime(2022, 10, 1, 15, 45, 35)]

You will just need to kick it off on whatever (even) week you want by setting the dtstart argument to the correct date. That, is described in this answer:

Datetime from year and week number

user_107892070

After thinking it over some more, I used the following rule:

list(rrule.rrule(freq=WEEKLY, byweekday=MO, byhour=12, byweekno=range(2, 54, 2), dtstart=datetime.datetime(year=2023, month=3, day=11), until=datetime.datetime(year=2023, month=5, day=31)))

... to create biweekly outputs:

[datetime.datetime(2023, 3, 20, 12, 0), datetime.datetime(2023, 4, 3, 12, 0), datetime.datetime(2023, 4, 17, 12, 0), datetime.datetime(2023, 5, 1, 12, 0), datetime.datetime(2023, 5, 15, 12, 0), datetime.datetime(2023, 5, 29, 12, 0)]

Using range to create a list of the 26 even week numbers feels a bit brute force for my taste, so I would love it if somebody else could suggest a more elegant approach.

user_2521940
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