__subclasses__() returns different subclasses in debugging mode and running

Question

I am learning inheritance and wrote a simple function to visualize subclasses, here is the code:

def PrintClassTree(thisclass, nest=0):
    if nest > 1:
        print('   |' * (nest - 1), end='')

    if nest > 0:
        print('   +---', end='')


    print(thisclass.__name__)

    for subclass in thisclass.__subclasses__():
        PrintClassTree(subclass, nest+1)

PrintClassTree(dict)

when I ran the function I got

dict
   +---OrderedDict
   +---defaultdict
   +---Counter

This is different from directly calling dict.__subclasses__(). When I ran in debugging mode, I got the following list, the same as calling dict.__subclasses__()

dict
   +---OrderedDict
   +---defaultdict
   |   +---Quoter
   +---Counter
   +---_EnumDict
   +---_QByteMap
   +---StgDict
   +---_ReqExtras
   +---ZipManifests
   |   +---MemoizedZipManifests
   +---TypedDict

I tried list and again, I can only get a full list of subclasses in debugging mode. I feel I am missing something here, but what makes debugging different from running the function?

I use Pycharm so both were done in the same IDLE. I couldn't find anything on this behavior. I tried BaseException and this seems to give me correct results when running the function.

subclasses() returns different subclasses in debugging mode and running

0 Answers