Regex - match first group regardless of second group

user_12099841 0
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I'm trying to match all URIs (of some specific pattern) without their suffix. My regex works when the address actually has a suffix, but I want it to also match cases where the suffix is already gone.

Regex:

(.+recordings\/.+)(\/.*)$

Matches:

https://somewebsite.com/recordings/10680-2162-4cff-991a-446ecff1/play
https://somewebsite.com/somethingsomething/recordings/10680-2162-4cff-991a-446ecff1/somesuffix

I'm trying to match this case as well:

https://somewebsite.com/recordings/10680-2162-4cff-991a-446ecff1

I've been playing with this for a couple of hours but unfortunately my knowledge of regex is limited.

you can test my regex here

Regex experts out there please help

regex-group regex
2 Answers

You can use

^(.*\/recordings\/.*?)(?:\/([^\/]*))?$

See the regex demo

Details:

  • ^ - start of string
  • (.*\/recordings\/.*?) - Group 1:
    • .* - any zero or more chars other than line break chars as many as possible
    • \/recordings\/ - a literal /recordings/ string
    • .*? - any zero or more chars other than line break chars as few as possible
  • (?:\/([^\/]*))? - an optional non-capturing group matching one or zero occurrences of
    • \/ - a / char
    • ([^\/]*) - Group 2: zero or more chars other than /
  • $ - end of string.
user_38329700

You could change the .+ at the end to \S to match non whitespace chars ad then optionally match the last part matching non whitespace chars without /

Depending on the regex delimiter, you don't have to escape \/

(\S+recordings\/[^\s\/]+)(?:\/[^\s\/]*)?$
  • ( Capture group 1
    • \S+recordings\/[^\s\/]+
  • ) Close group 1
  • (?:\/[^\s\/]*)? Optionally match / and the rest of the line withtout /
  • $ End of string

Regex demo

Or match the protocol and optional non whitespace chars

^(https?:\/\/\S*\/recordings\/[^\s\/]+)(?:\/[^\s\/]*)?$

Regex demo

user_54249880
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