I have a regex that is not working on Safari because it contains lookbehind which is not supported:
\b((a[a-c])[^\"]*(?<![0-9])2(?![0-9])[^\"]*)
is there any alternative that does EXACTLY what the regex above does? (the character right before the 2 must NOT be a digit so this will pass aa4a2 but not this aa4a22
Thanks.
You can use
\b((a[a-c])(?:[^\"]*[^\"0-9])?2(?![0-9])[^\"]*)
The (?:[^\"]*[^\"0-9])? part is a non-capturing group matching one or zero occurrences of any zero or more chars other than " and then any one char that is not a " and a digit.
Note that the consuming character of the added group is fine here since the [^\"]* pattern was able to match an empty string, hence the use of the optional non-capturing group.