struct string variable assignment in C

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#include <stdio.h>

struct Student {
    char name[10];
    int age;
    double gpa;
};

int main(void)
{
    struct Student s1;
    s1.age = 20;
    s1.gpa = 4.3;
    s1.name[10] = "Tom";

    printf("%s", s1.name);

    return 0;
}

I know 'strcpy' function or other way to assign string. but Why doesn't it work above code..? Please help me.

Specially, s1.name[10] = "Tom";

Thanks.

struct c
2 Answers

There are few issues with this statement:

s1.name[10] = "Tom";

In C array (of length n) indexing starts with 0 and ends at n-1. Accessing any elements out side of 0 to n-1 (both inclusive) will cause undefined behaviour. s1.name[10] is out of bound access and not valid.

Another problem is that you cannot assign a string literal to an array using assignment operator except when it is used in the initializer. You have to use strcpy to copy a string literal to a char array. Make sure length of string literal must not exceed the size of the array (make sure there is a room for \0).

user_24558880

In this expression statement

s1.name[10] = "Tom";

the left side operand has the type char. Moreover in this expression s1.name[10] there is dereferenced pointer that points outside the allocated array.

The right side operand after the implicit conversion has the type char *.

So you are trying to assign a pointer to a non-existent element of the array.

Pay attention to that arrays do not have the assignment operator.

You could initialize the object of the structure type when it is defined like

 struct Student s1=
 {
    .name = "Tom",
    .age = 20,
    .gpa = 4.3
};
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