How to write a bash script to copy files from one base to another base location

user_19509630 0
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I have a bash script I'm trying to write I have 2 base directories:

  • ./tmp/serve/
  • ./src/

I want to go through all the directories in ./tmp and copy the *.html files into the same folder path in ./src

i.e if I have a html file in ./tmp/serve/app/components/help/ help.html --> copy to ./src/app/components/help/ And recursively do this for all subdirectories in ./tmp/

NOTE: the folder structures should exist so just need to copy them only. If it doesn't then hopefully it could create the folder for me (not what I want) but with GIT I can track these folders to manually handle those loose html files.

I got as far as

echo $(find . -name "*.html")\n

But not sure how to actually extract the file path with pwd and do what I need to, maybe it's not a one liner and needs to be done with some vars.

bash
4 Answers

something like

for i in `echo $(find /tmp/ -name "*.html")\n
do
    cp -r $i /src/app/components/help/
done

going so far to create the directories would take some more time for me. I'll try to do it on my own and see if I come up with something but for argument sake if you do run pwd and get a response the pseudo code for that:

  1. pwd
  2. get response
  3. if that directory does not exist in src create that directory
  4. copy all the original directories contents into the new folder at /src/$newfolder (possibly running two for loops, one to check the directory tree, and then one to go through each original directory, copying all the html files)
user_195102570

You process substitution to loop the output from your find command and create the destination directory(ies) and then copy the file(s):

#!/bin/bash

# accept first parameters to script as src_dir and dest values or 
# simply use default values if no parameter(s) passed
src_dir=${1:-/tmp/serve}
dest=${2-src}

while read -r orig_path ; do
    # To replace the first occurrence of a pattern with a given string, 
    # use ${parameter/pattern/string}
    dest_path="${orig_path/tmp\/serve/${dest}}"

    # Use dirname to remove the filename from the destination path
    # and create the destination directory.
    dest_dir=$(dirname "${dest_path}")
    mkdir -p "${dest_dir}"
    
    cp "${orig_path}" "${dest_path}"
done < <(find "${src_dir}" -name '*.html')
user_164829380

This script copy .html files from src directory to des directory (create the subdirectory if they do not exist)

Find the files, then remove the src directory name and copy them into the destination directory.

#!/bin/bash
for i in `echo $(find src/ -name "*.html")`
do
  file=$(echo $i | sed 's/src\///g')
  cp -r --parents $i des
done
user_135956150

Not sure if you must use bash constructs or not, but here is a GNU tar solution (if you use GNU tar), which IMHO is the best way to handle this situation because all the metadata for the files (permissions, etc.) are preserved:

find ./tmp/serve -name '*.html' -type f -print0 | tar --null -T - -c | tar -x -v -C ./src --strip-components=3

This finds all the .html files (-type f) in the ./tmp/serve directory and prints them nul-terminated (-print0), then sends these filenames via stdin to tar as nul-terminated literals (--null) for inclusion (-T -), creating (-c) an archive which is then sent to another tar instance which extracts (-x) the archive printing its contents along the way (optional: -v), changing directory to the destination (-C ./src) before commencing and stripping (--strip-components=3) the ./tmp/serve/ prefix from the files. (You could also cd ./tmp/serve beforehand, using find . instead, and change -C to ../../src.)

user_32770640
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