How to cast integer as tuple of bool

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I have an integer, and would like to cast it as a tuple of boolean-likes— {0, 1} specifically. The way which comes to mind is tuple(int(b) for b in bin(my_int)[2:]), but feels off. What is the idiomatic/canonical way perform this?

Edit: for clarity, if the integer is 3, the tuple would be (0, 0, 0, 0, 0, 0, 1, 1). To further clarify, assume the integer is in {0, 1, …, 255} and the tuple’s length should be eight. So what I have at this point (but aim to improve) is tuple(int(b) for b in bin(my_int)[2:].zfill(8))

python
1 Answers

I don't think your way is bad, but I found another one:

def to_binary(num):
    result = []
    while num >= 1:
        result.insert(0, num%2)
        num//=2
    return result
print(to_binary(5))
>>> [1, 0, 1]

Or you can add via append and at the end reverse via [::-1]. To be honest, I don't remember which is faster.

UPD [07.07.2022]

As I understand it, you need a tuple, and if its length is less than eight characters, you need to complement it with 0 on the left.

In this case, the code will change a little:

def to_binary(num):
    result = []
    while num >= 1:
        result.insert(0, num%2)
        num//=2
    result =  tuple([0] * (max(8-len(result), 0)) + result)
    return result

Or you can also update your code by adding zfill method:

your_tuple = tuple(int(b) for b in bin(3)[2:].zfill(8))
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