URL=example.com
#URL=example.com:8080
PORT=${URL#*:}
PORT=${PORT:-8080}
I want to do the parameter substitution with remove pattern and the default in one line.
Is the a way to set default when parameter substitution is empty?
Set default value after parameter substitution with remove pattern
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2 Answers
For doing this in a one step in bash, you can use read with IFS=: with a default value appended to url variable like this:
url='example.com:7000'
IFS=: read host port _ <<< "$url:8080"
# check host and port values
declare -p host port
echo '------'
url='example.com'
IFS=: read host port _ <<< "$url:8080"
# check host and port values
declare -p host port
Output:
declare -- host="example.com"
declare -- port="7000"
------
declare -- host="example.com"
declare -- port="8080"
One option is:
[[ $url == *:* ]] && port=${url#*:} || port=8080
- See Correct Bash and shell script variable capitalization for an explanation of why I replaced
URLandPORTwithurlandport.
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