Question about 'or' and 'and' operators in R?

user_3447708 0
Viewed 34

I have a general question about the or and and operators in R.

In the below example, I am assigning a value to 2 variables x and y and Im just doing some logical operations on them. But when I wrap the expression in parenthesis, the result changes... and I'm wondering why or what is the logic behind this? For example:

x = 10
y = 2

# x or y is equal to 2
>x|y == 2
[1] TRUE

But when I add parenthesis:

> (x|y) == 2 
[1] FALSE

Additionally, if I just check the x:

> x|x == 2
[1] TRUE
> (x|x) == 2 
[1] FALSE

Similarily for &:

> x&y == 2
[1] TRUE
> (x&y)==2
[1] FALSE

I know this might be a basic question, but the logic behind this isn't as intuitive as I originally thought! I know there are lots of resources online talking about these operators.. but none of them seem to answer this type of question directly. I was wondering what is exactly going on here?

r
1 Answers

The reason relates to conversion of non-zero values to TRUE and zero to FALSE

> as.logical(x)
[1] TRUE
> as.logical(0)
[1] FALSE

When we use | (OR), it checks whether any of the elements are non-zero, and thus returns TRUE, whereas in &, both elements should be non-zero

> x|y
[1] TRUE

and when we compare with 2, it is not equal because the lhs is logical, when coerced to 1 (binary values correspond to TRUE/FALSE for 1/0), and rhs is 2

> (x|y) == 2 
[1] FALSE
> (x|y) == 1
[1] TRUE

In addition, there is operator precedence when we don't wrap them inside brackets

x&(y == 2)
[1] TRUE

It returns TRUE because x is non zero, and y ==2 returns TRUE, thus both returns TRUE

> y==2
[1] TRUE
user_37322710
Related