regex groups with uneven number of groups

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I'm not good with terms used in regex, so picking a suitable title for this question is some how difficult for me, so feel free the suggest a good title.

but anyway I have this txt and regex expression

import re
txt = """
%power {s}
shop %power {w}
%electricity {t}
""".replace('\n',' ')
x = re.findall("((\%?\w+\s)*)\{([^\}]*)\}",txt)

the result is

[('%power ', '%power ', 's'), ('shop %power ', '%power ', 'w'), ('%electricity ', '%electricity ', 't')] but I was intended to get

[('%power ', 's'), ('shop ', '%power ', 'w'), ('%electricity ', 't')] so how can I achieve the desired?

python-re regex-group regex
1 Answers

You need to pip install regex and then use

import regex
txt = """
%power {s}
shop %power ow {w}
%electricity {t}
""".replace('\n',' ')
x = regex.finditer(r"(%?\w+\s)*\{([^{}]*)}", txt)
z = [tuple(y.captures(1) + y.captures(2)) for y in x] 
print(z)

See the Python demo.

Output:

[('%power ', 's'), ('shop ', '%power ', 'ow ', 'w'), ('%electricity ', 't')]

NOTE on regex.finditer usage

The regex.finditer method returns an iterable, not a list. It has an implication that you cannot re-use the x inside a list comprehension. In order to re-use the contents of x, either convert it to a list (list(x)), or use the approach above, use it only once to get the necessary output structure, and do whatever you need with the result.

user_38329700
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