I am using the following command to compile a specific python script:
python3 -m py_compile abc.py
However I want this compiled file to reside in a different directory. I haven't been able to find anything over the internet regarding this. Is this even possible? So, I am trying something like:
python3 -m py_compile abc.py /Users/documents/abc.pyc
ofcourse the above command gives an error saying it can't find the file or directory /Users/documents/abc.pyc.
I think it's impossible to specify named arguments with -m option. If -m is necessary, you can create a wrapper that runs py_compile and pass arguments with sys.argv.
$ cat compile_it.py
import sys
import py_compile
# cfile` is named argument for destination filename
py_compile.compile(sys.argv[1], cfile=sys.argv[2])
And use it with:
python -m compile_it abc.py /Users/documents/abc.pyc
Or without -m:
python compile_it.py abc.py /Users/documents/abc.pyc