How to append a character between two characters in Bash

user_11549510 0
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I have a list as below;

paramone=somerandomvalue; paramtwo=somerandomvalue; paramthree=somerandomvalue;

I want to append a * (asterisk) at the end of every 'somerandomvalue' but before ; (semicolon) like below -

paramone=somerandomvalue*; paramtwo=somerandomvalue*; paramthree=somevrandomalue*;

NOTE - It should only append the strings that have = and ; . There are other strings having ; at the end but doesn't have a =.

sed shell linux bash
3 Answers

I'd leverage sed to do this:

sed 's/;/*;/g' test.txt

Something like that. Assuming every value has that ; at the end of it.

user_19784120

Assuming your input had the following content

$ cat input_file
paramone=somerandomvalue; paramtwo=somerandomvalue; paramthree~somerandomvalue;paramone=somerandomvalue; paramtwo=somerandomvalue; paramthree##somerandomvalue;

Using sed

$ sed s'/\(=[^;]*\)/\1*/g' input_file
paramone=somerandomvalue*; paramtwo=somerandomvalue*; paramthree~somerandomvalue;paramone=somerandomvalue*; paramtwo=somerandomvalue*; paramthree##somerandomvalue;
user_163721090

This should also work - sed s'/=\(.*\)?;/\1*/g' <input_file_name>

user_141134320
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