Select and Count Multiple Group By SQL

user_16296326 0
Viewed 54

Can someone tell me how to do this in Database?

Select and Count Multiple Group By SQL

I've tried some sql like:

SELECT disastertype, YEAR(eventdate) as year,
        COUNT(disastertype) AS disastertype_total
        FROM v_disasterlogs_all 
WHERE YEAR(eventdate) >= year(CURRENT_TIMESTAMP) - 4 
GROUP BY YEAR(eventdate) 
ORDER BY YEAR(eventdate) ASC

But, it only shows like this:

Result

sql
2 Answers

include disastertype on our group by statement.

SELECT disastertype, YEAR(eventdate) as year,
        COUNT(disastertype) AS disastertype_total
        FROM v_disasterlogs_all 
WHERE YEAR(eventdate) >= year(CURRENT_TIMESTAMP) - 4 
GROUP BY YEAR(eventdate), disastertype
ORDER BY YEAR(eventdate) ASC
user_64290720

I am assuming you want a count (the column index) to be associated with each unique year?

In this case, a possible solution in postgres will be as below.

select
    dense_rank() over (order by date_part('year', (eventdate))) as index ,
    date_part('year', (eventdate)) as year,
    disastertype,
    count(disastertype)
from
    v_disaterlogs_all
where
    date_part('year', (eventdate)) >= date_part('year', now()) - 4
group by
    year,
    disastertype
order by
    year asc;

In postgres, I have used the function date_part to extract the year from the timestamp.

Working solution on dbfiddle.

user_62003540
Related