Avoiding a checked exception in a constructor

Problem

I have a class with two constructors. One of them (A) throws a checked exception, and the other one (B) calls the first one.

// Constructor A
public ArrayValue(DataType rules, Value... content) throws NonExpressionException {
    super(rules.type);
    ...
}

// Constructor B
public ArrayValue(Value... content) {
    this(TypeConstants.VAR_ARR, content);
}

The problem is, that this checked exception will never get thrown when constructor B is invoked, so I thought of "catching" it instead of adding a "throws" to this constructor.

Question

What can I do to get rid of the "throws"? My conditions are:

• The first constructor has to throw this exception.
• It has to be checked.
• I dont want to copy the whole code from constructor A into B.
• I'm looking for a more elegant solution than just changing the constructor B to a static method.

I have tried

// Constructor B
public ArrayValue(Value... content) {
    try {
        this(TypeConstants.VAR_ARR, content));
    catch (NonExpressionException e) {
        throw new AssertionError("This shouldn't get thrown", e);
    }
}

(But that doesn't work, because this() has to be the first statement in a constructor.)