Java Stream: Parsing Strings inside the reduce() operation

user_12465838 0
Viewed 79

I have a stream of strings:

Stream<String> st = Arrays.stream(new String[]{"10", "20", "30",  "40", "50"});

I want to convert them to integer and sum them up using the reduce method. I'm using reduce in the following format:

int result = st.reduce(0, (a, b) -> a + Integer.parseInt(b));

I get this error:

no suitable method found for reduce(int, (a, b) -> a + [...]nt(b))

any hint about how can I rewrite the reduce method to make it work?

java-stream java string
3 Answers

You need to provide a combiner function as the third argument to make it work:

int sum = Arrays.stream(new String[]{"10", "20", "30",  "40", "50"})
            .reduce(0, (a, b)-> a + Integer.parseInt(b), Integer::sum);

Otherwise you're getting the different flavor of reduce() which is capable of produce the result of the same type as the type of elements in the stream.

And you don't need reduce(), the better way:

int sum = Stream.of("10", "20", "30",  "40", "50")
            .mapToInt(Integer::parseInt)
            .sum();
user_179499450

Instead of using reduce(), I'd break it into two steps: Convert the strings to ints (As an IntStream), and then sum them:

Stream.of("10", "20", "30", "40", "50").mapToInt(Integer::parseInt).sum()
user_99521960

I want to convert them to integer and sum them up using the reduce method. I am using reduce in the following format:

When converting to an IntStream via Integer::parseInt the reduce method takes a form of an int starting value and an IntBinaryOperator. So the following will work.

String[] data ={"10", "20", "30",  "40", "50"};
int sum = Arrays.stream(data)
           .mapToInt(Integer::parseInt).reduce(0, (a,b)->(a+b));
System.out.println(sum);

prints

150

And for your edification (and future requirements) you can do it like so.

int sum = Arrays.stream(data).mapToInt(Integer::parseInt).sum();
System.out.println(sum);

prints

150
user_15525340
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