Move the bottom of a curve without changing both ends

user_11422689 0
Viewed 49

I'm having a curve as follows:

enter image description here

The curve is generated with the following code:

import matplotlib.pyplot as plt
import numpy as np

# normalize array
def min_max_scale_array(arr):
    arr = np.array(arr)
    return (arr - arr.min())/(arr.max()-arr.min())

x = np.linspace(-50,48,100)
y = x**2 + 2*x + 2  

x = min_max_scale_array(x)
y = min_max_scale_array(y)

fig, ax = plt.subplots()
ax.plot(x, y)

How can I generate a new curve by moving only the bottom left (or right) and keeping both ends the same like this? Thank you!

enter image description here

Edit: any curve generating algorithm is appreciated, as long as it works!

numpy python
2 Answers

One way of doing so is defining x,y as before, but applying a shift. The dotted line shows if you just shift it. But now at the top most y we don't want to shift it, so we'd like to weight the shifted version on the bottom (y=0) by 1 but on the top (y=1) by 0 such that we get a gradual interpolation. We can do this by multiplying the shift by (1-y):

enter image description here

a = 0.25  # how far to shift left
plt.plot(x, y, 'k')
plt.plot(x-a, y, 'k:')
plt.plot(x-a*(1-y), y, 'r')
plt.show()
user_29131060

Easiest solution: apply a sublinear transformation to x - a quadratic function will work.

x = x**2  # works because x is scaled to 0-1
ax.plot(x, y)

enter image description here

UPD: as requested, a scaling factor would look something like:

scaling_factor = 0.7
x = scaling_factor*(x**2) + (1-scaling_factor)*x

enter image description here

user_2716410
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