Create dictionary out of txt file. One alphabet letter per row. Key is letter and value should be iteration of the loop

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i got a problem.. I have a txt file that looks like this:

a
b
c
d

One letter per row, there is not two values per row, so nothing to split..

This code works, if I add a second value in my alphabetFile.
dict = {}
with open("alphabet.txt") as alphabetFile:
    for line in alphabetFile:
        (key, val) = line.split()
        dict[int(key)] = val

print(dict)

But I should only have 1 value per row... Im thinking the iteration should be the second value.. but im stuck and tired.. any ideas?

dictionary python
1 Answers

You can use enumerate() to iterate over lines. Also, don't use dict as name of variable (it shadows Python built-in):

dct = {}
with open("alphabet.txt") as alphabetFile:
    for iteration, line in enumerate(alphabetFile, 1):
        dct[line.strip()] = iteration

print(dct)

Prints:

{'a': 1, 'b': 2, 'c': 3, 'd': 4}
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