How to transform list with subelements in a dataframe R?

user_11895692 0
Viewed 37

I have this:

res.list<-list(
    list(
        structure(list(A = 1L, B = "X2", D = 1L), class = "data.frame", row.names = c(NA, -1L)),
        structure(list(A = 1L, B = "X3, X14, X17", D = 3L), class = "data.frame", row.names = c(NA, -1L)),
        structure(list(A = 1L, B = "X4, X14, X17", D = 3L), class = "data.frame", row.names = c(NA, -1L)))
    ,
    list(
        structure(list(A = 2L, B = "X17, X19", D = 2L), class = "data.frame", row.names = c(NA, -1L)),
        structure(list(A = 2L, B = "X2, X17, X19", D = 3L), class = "data.frame", row.names = c(NA, -1L)),
        structure(list(A = 2L, B = "X3, X17, X19", D = 3L), class = "data.frame", row.names = c(NA, -1L))))

What is the most efficient and generic way to do the procedure below?

rbind(do.call(rbind.data.frame,res.list[[1]]),
            do.call(rbind.data.frame,res.list[[2]]))

Best regards;

dataframe r list
1 Answers

It may be easier with bind_rows

library(dplyr)
bind_rows(res.list)
  A            B D
1 1           X2 1
2 1 X3, X14, X17 3
3 1 X4, X14, X17 3
4 2     X17, X19 2
5 2 X2, X17, X19 3
6 2 X3, X17, X19 3
user_37322710
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