How to delete an element from a tuple based on a condition?

You just need to check if Value variable is holding anything or not. If it does then append the item in list otherwise don't.

So as you asked for a solution to be implemented in another if condition, you can do as follows:

if Value:
    data.append([myList[0], Value])

Here, blank string "" is considered as False, so the item won't be appended if Value is a blank string.

import ast
data = []

myList=[0,"[('AA', 'BB'), ('CC', 'DD'), ('EE', 'FF'), ('GG', 'HH')]"]
 
for a in ast.literal_eval(myList[1]):
                
    Value = a[0]
    Type = a[1]
    
    if(Type == "BB"):
        Value="XX"
                    
    if(Type == "DD"):
        Value="YY" 
                    
    if(Type == "FF"):
        Value=""

    if not Value == "":
        data.append([myList[0], Value]) 
print(data)
# [[0, 'XX'], [0, 'YY'], [0, 'GG']]

You can also make your code shorter, more clear and more Pythonic like so:

import ast
data = []

my_lst = [0, "[('AA', 'BB'), ('CC', 'DD'), ('EE', 'FF'), ('GG', 'HH')]"]

type_to_val = {'BB': 'XX', 'DD': 'YY', 'FF': ''}

for tup in ast.literal_eval(my_lst[1]):       
    (cur_val, cur_type) = tup
    try:
        cur_val = type_to_val[cur_type]
    except KeyError:
        pass
    if cur_val != "":
        data.append([my_lst[0], cur_val]) 
print(data)

You could "filter" out data that you append within the last value. i.e. you prevent appending that data entry to the list if it doesn't meet the requirements you set. There are a few ways you could do this

1. You could set it to only append values that match the condition

import ast
data = []

myList=[0,"[('AA', 'BB'), ('CC', 'DD'), ('EE', 'FF'), ('GG', 'HH')]"]
 
for a in ast.literal_eval(myList[1]):
                
    Value = a[0]
    Type = a[1]
    
    if(Type == "BB"):
        Value="XX"
                    
    if(Type == "DD"):
        Value="YY" 
                    
    if(Type != "FF"):                   
        data.append([myList[0], Value])

print(data)

2. Alternatively you could use continue to skip the last part of the loop. This one looks nicer and keeps your code consistent. continue tells python to "skip everything until the next loop".

import ast
data = []

myList=[0,"[('AA', 'BB'), ('CC', 'DD'), ('EE', 'FF'), ('GG', 'HH')]"]
 
for a in ast.literal_eval(myList[1]):
                
    Value = a[0]
    Type = a[1]
    
    if(Type == "BB"):
        Value="XX"
                    
    if(Type == "DD"):
        Value="YY" 
                    
    if(Type == "FF"):
        continue
                   
    data.append([myList[0], Value])

print(data)

Both should give you the result you are looking for

An easy way to achieve this would be to use the continue statement in your third conditional. Continue statements can be used in loops to skip the execution of the remaining code in the loop and return control to the beginning of the loop at the next iteration.

In your case:

    if(Type == "FF"):
        continue
                   
    data.append([myList[0], Value])

would mean that if type is 'FF' then the data.append statement is skipped and the entry is not added to your list.

You can do everything needed it a list comprehension:

import ast

myList=[0,"[('AA', 'BB'), ('CC', 'DD'), ('EE', 'FF'), ('GG', 'HH')]"]

data = [(myList[0], value) for value, type_ in ast.literal_eval(myList[1] if type_ != "FF"]

print(data)