Dictionary with list as values and only want the first element like "code:%"

user_13287802 0
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So I have a dictionary with data

dict = {1:["code: 1", "date: 01-01-2000", "date: 01-02-2000", "date: 01-03-2000", "spent: 20$"]}

I want to get this output:

{1:["code: 1",  "date: 01-01-2000", "spent: 20$"]}

So basically I only want the first element that have "date:" and the rest of elements

How can i obtain this?

python-3.x list dictionary
2 Answers
d = {1:["code: 1", "date: 01-01-2000", "date: 01-02-2000", "date: 01-03-2000", "spent: 20$"]}
a=[]
x=d[1][0:2]
y=d[1][-1]
a.append(x)
x.append(y)
output={1:x}
print(output)
user_143255120

Try:

dct = {
    1: [
        "code: 1",
        "date: 01-01-2000",
        "date: 01-02-2000",
        "date: 01-03-2000",
        "spent: 20$",
    ]
}

out = {}
for k, v in dct.items():
    tmp = {}
    for i in reversed(v):
        tmp[i.split(":")[0]] = i
    out[k] = list(reversed(tmp.values()))

print(out)

Prints:

{1: ['code: 1', 'date: 01-01-2000', 'spent: 20$']}
user_100359850
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