Minimum value from a dictionary based on value in secondary list

user_13859413 0
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I have a list and a dictionary:

lst = ['Boston', 'Denver']
dic = {'Atlanta': 0, 'Boston':100, 'Denver':160}

I want to find the dictionary key that has the lowest value provided the key is in the list. In this case, I want to return 'Boston' rather than 'Atlanta' since it is not contained in the list. How would I search for the minimum value efficiently?

list dictionary python
3 Answers

I would do this:

min(lst, key=dic.get)
user_114611200

Try:

k = min(dic.keys() & lst, key=dic.get)
print(k)

Prints:

Boston
user_100359850

You can use min() with a key parameter that associates a value of inf to any key that doesn't appear in the list:

min(dic.keys(), key=lambda x: dic[x] if x in lst else float('inf'))

This outputs:

Boston
user_177698150
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