How to return array of objects by checking its property and arraylist in javascript

user_18743604 0
Viewed 61

how to compare array of objects with arrays using javascript

I need to check array of objects based on conditons

  1. if the targetvalue is same and code does not have value in arraylist return array of objects

  2. else if the targetvalue is same and code same value in arraylist return array of objects

else return []

var arraylist =["IT","FI"];
var arrobj1 =[
  {id:1, name: "sonu", code: "IT", targetvalue: "908"},
  {id:2, name: "abi", code: "IT", targetvalue: "834"},
  {id:3, name: "lisa", code: "SP", targetvalue: "834"},
  {id:4, name: "ben", code: "FI", targetvalue: "234"},
]

Expected Output 
//same value , and has "IT" 
[]

****

var arrobj2 =[
  {id:1, name: "sonu", code: "IT", targetvalue: "908"},
  {id:2, name: "abi", code: "IT", targetvalue: "834"},
  {id:3, name: "lisa", code: "SG", targetvalue: "234"},
  {id:4, name: "ben", code: "SP", targetvalue: "234"},
]

Expected Output
//same targetvalue and no include of `FI or IT` so return
[
 {id:3, name: "lisa", code: "SG", targetvalue: "234"},
  {id:4, name: "ben", code: "SP", targetvalue: "234"},
] 


****

var arrobj3 =[
  {id:1, name: "sonu", code: "IT", targetvalue: "908"},
  {id:3, name: "lisa", code: "FI", targetvalue: "234"},
  {id:4, name: "ben", code: "FI", targetvalue: "234"},
]
Expected Output
// targetvalue and code same
 [ {id:3, name: "lisa", code: "FI", targetvalue: "234"},
  {id:4, name: "ben", code: "FI", targetvalue: "234"}]

I tried

const checkIdList = list => {
    const idlist = ['IN', 'FI'];
    const resultarray = list
      .map((obj, i) => list.find((elem, index) => {
        if (i !== index && elem.targetvalue === obj.targetvalue && 
           (element.code === obj.code || idlist.includes(element.code)) {
          return obj;
        }
      }))
      .filter(x => x);
    return resultarray;
  };
var finalResult = this.checkIdList(arrobj1);
arrayobject object arrays loops javascript
1 Answers

You can start by grouping the elements by targetValue and then filter the Object.values of the result by your three conditions:

function checkIdList(array, list) {
  // group by targetValue
  const grouped = {};
  for (const o of array) {
    (grouped[o.targetvalue] ??= []).push(o);
  }

  return Object.values(grouped)
    .filter(g =>
      g.length > 1  // subarrays of length > 1 indicate duplicates
      && (
        g.every(({ code }) => !list.includes(code)) || // if every code is not in the list
        g.every(({ code }, _, a) => code === a[0].code) // OR include if all codes are equal and included in list
      ))
    .flat();
}

const arraylist = ["IT", "FI"];
const arrobj1 = [{ id: 1, name: "sonu", code: "IT", targetvalue: "908" }, { id: 2, name: "abi", code: "IT", targetvalue: "834" }, { id: 3, name: "lisa", code: "SP", targetvalue: "834" }, { id: 4, name: "ben", code: "FI", targetvalue: "234" },];
const arrobj2 = [{ id: 1, name: "sonu", code: "IT", targetvalue: "908" }, { id: 2, name: "abi", code: "IT", targetvalue: "834" }, { id: 3, name: "lisa", code: "SG", targetvalue: "234" }, { id: 4, name: "ben", code: "SP", targetvalue: "234" },];
const arrobj3 = [{ id: 1, name: "sonu", code: "IT", targetvalue: "908" }, { id: 3, name: "lisa", code: "FI", targetvalue: "234" }, { id: 4, name: "ben", code: "FI", targetvalue: "234" },];

console.log(checkIdList(arrobj1, arraylist));
console.log(checkIdList(arrobj2, arraylist));
console.log(checkIdList(arrobj3, arraylist));

user_137623010
Related