Remove empty values from array of objects only if the value is empty in all objects

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I'm trying to remove the empty strings in my array.

This is my array:

let array = [{name:'John',age:'18',address:''},{name:'George',age:'',address:''},{name:'Kevin',age:'25',address:''}]

I would like to remove the empty string values ONLY if it's empty in all objects.

desired outcome:

[{name:'John',age:'18'},{name:'George',age:''},{name:'Kevin',age:'25'}]

This is what I did but it removes EVERY empty string values:

 for (let i = 0; i < array.length; i++) {
 array[i] = Object.fromEntries(Object.entries(array[i]).filter(([_, v]) => v != ''));
 }

Thanks in advance ,

3 Answers

If you don't mind mutating the original array object. Here's a solution utilizing some array functions.

let array = [
  { name: 'John', age: '18', address: '' },
  { name: 'George', age: '', address: '' },
  { name: 'Kevin', age: '25', address: '' }
]

Object.keys(array[0])
  .filter(k => array.every(obj => !obj[k]))
  .forEach(k => array.forEach(obj => delete obj[k]));

console.log(array);

You can solve this issue with a filter method

  • get all the entries to be scanned in the array;
  • for each entry, filter the array with it; if the output array is empty then you can delete this value in the original array

    let array = [{name:'John',age:'18',address:''},{name:'George',age:'',address:''},{name:'Kevin',age:'25',address:''}]
    
    const entries = Object.keys(array[0])
    
    entries.forEach(e => {
        if(array.filter(i => i[e]).length === 0) {
          array = array.map(i => {delete i[e]; return i})
        }
    })
    
    console.log(array)

If you don't want to mutate the original array:

let array = [{name:'John',age:'18',address:''},{name:'George',age:'',address:''},{name:'Kevin',age:'25',address:''}]


let result;

Object.keys(array[0])
.forEach(key => {
    if(array.every(e => e[key] === ''))
        result = array.map(({[key]:_,...rest}) => ({...rest}))
})

console.log(result)

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