I have a list that looks like this:
['','2022-03-31', 'euss', 'projects','2021-03-31']
I want to write a regular expression such that I delete all other items from the list and only keep those that have a date format. For example, 2022-03-31 and 2021-03-31.
I tried this but it doesn't seem to make a difference when I print my list out:
my_list = [re.sub(r"(\d+)/(\d+)/(\d+)",r"\3-\1-\2",i) for i in list(my_list) ]
You can first check if there regex matches the string:
result = []
rx = re.compile(r'(\d+)-(\d+)-(\d+)')
for i in my_list:
if rx.search(i): # Check if the regex matches the string
result.append(rx.sub(r"\3-\1-\2", i)) # Add modified string to resulting list
See the Python demo. Output:
['31-2022-03', '31-2021-03']
You may write it as:
rx = re.compile(r'(\d+)-(\d+)-(\d+)')
my_list = [rx.sub(r"\3-\1-\2", i) for i in my_list if rx.search(i)]