Python makes wrong comparison of two booleans

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I have this line of code:

print(isIndent(idxA), idxA[0]<idxB[0], isIndent(idxA) == idxA[0]< idxB[0])

In the code, I just test if the first statement has the same value as the second.

isIndent is a predicate and idxA and idxB are both tuples, but I run it I have this: True True False

So the two members are both True, but the equality is False

So as you might expect, I just want a way to compare reliably the two expressions in a single row (without creating any temp value storage....)

compare boolean python
1 Answers

If you take a look at this part:

isIndent(idxA) == idxA[0]<idxB[0]

It says: if (isIndent(idxA) == idxA[0]) < idxB[0]

it uses comparison chaining (thanks @Barmar) Which means it becomes:

if (isIndent(idxA) < idxB[0]) and (idxA[0] < idxB[0])

Because of the order it was written in!

In order to change that behaviour, use parenthesis

print(isIndent(idxA), idxA[0]<idxB[0], isIndent(idxA) == (idxA[0]<idxB[0]))
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