A have the line in file acounts.list
['# name prueba7@prueba7.com', 'zimbraIsDelegatedAdminAccount: TRUE']
I would like to remove ['# name, all ' and '] What would the result be prueba7@prueba7.com, zimbraIsDelegatedAdminAccount: TRUE
I tried to create task to remove first ['# name
- lineinfile:
dest: /home/acounts.list
state: absent
regexp: "^\[\'\#\sname\s"
... but i got error. Could you please help with solution? Thank you.
use replace instead:
- name: replace
ansible.builtin.replace:
path: /home/acounts.list
regexp: "['\\[\\]]|# *name *"
replace: ''
you could write too: regexp: '[''\[\]]|# *name *'
['\\[\\]] means replace all ' or [ or ] (or == [])
so as [ and ] are special char, you ahve to protect by \ with " you have to protect \ too by another \ (not needed when surrounded by ')
| means or and the other expression is # *name * * means zero or more space