I am stuck in writing a loop in assembly to read 5 characters and print them in reverse order

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.data

.code
main proc

        mov cx,5
        user_input:
        
        mov ah,1h
        int 21h
        push dx
        
        loop user_input
        
        
        mov cx,5
        system_output:
        
        
        mov ah,2h
        int 21h
        pop dx
        
        loop system_output
    
    
    
    endp

I want to write a code that gets 5 numbers from the User and print all five of them in reversed order my code

the program gets 5 numbers but does nothing and dies.

and I still cant find my numbers in Stack, and I put the screen shot below.

x86-16 dos assembly loops
1 Answers

The AH=1 function gives you a character in the AL register. You should use push AX in the first loop! (instead of push dx)

In the second loop you should use pop DX before doing function AH=2.

And best end your program with:

mov ax, 4C00h
int 21h
user_31447700
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