How to render HTML in python?

user_18271396 0
Viewed 1706

This code does not work for me

I would like to know a way to render html using python without tkinterhtml

When loading google.com, I get the error:

Exception in Tkinter callback
Traceback (most recent call last):
  File "c:\python scripts\project\file.py", line 10, in search
    html = htmlBytes.decode("utf8")
UnicodeDecodeError: 'utf-8' codec can't decode byte 0xe7 in position 10955: invalid continuation byte

During handling of the above exception, another exception occurred:

Traceback (most recent call last):
  File "C:\Users\user\AppData\Local\Programs\Python\Python310\lib\tkinter\__init__.py", line 1921, in __call__
    return self.func(*args)
  File "c:\python scripts\project\file.py", line 12, in search
    html = htmlBytes.decode("utf16")
UnicodeDecodeError: 'utf-16-le' codec can't decode byte 0x3e in position 14624: truncated data

I am working on this for a project and am launching the code using the import keyword. My code doesn't work and closes the window after the search funtion finishes.

import urllib.request
import tkinter
from tkinterhtml import HtmlFrame

def search():
    url = urlInput.get()
    page = urllib.request.urlopen(url)
    htmlBytes = page.read()
    try:
        html = htmlBytes.decode("utf8")
    except:
        html = htmlBytes.decode("utf16")
    frame.set_content(html)

    page.close()

screen = tkinter.Tk()
screen.geometry("700x700")
frame = HtmlFrame(screen, horizontal_scrollbar="auto")
urlInput = tkinter.Entry(screen)
urlInput.grid(column=0,row=0,columnspan=10,rowspan=4,sticky="news")
searchBtn = tkinter.Button(screen,text="search",command=search)
searchBtn.grid(row=0,column=11,sticky="news")
screen.mainloop()
tkinter html python
4 Answers

tkinter does not have the ability to render HTML. You'll have to use a third-party library. Since you explicitly said you don't want to use tkinterhtml you'll have to find some other third-party renderer.

user_74320

You're decoding the google.com page as 'utf8' or 'utf16'; however, the google.com page uses the ISO-8859-1 encoding:

The header returned by google.com is:

Content-Type: text/html; charset=ISO-8859-1

You will need to decode the page using 'ISO-8859-1' to avoid the "codec can't decode byte 0x.." errors.

user_6833290

I have fixed this by using the tkinterweb library.

Code:

import tkinter
from tkinterweb import HtmlFrame

screen = tkinter.Tk()
screen.geometry("700x700")
frame = HtmlFrame(screen, horizontal_scrollbar="auto")
urlInput = tkinter.Entry(screen)

def search():
    frame.load_website(urlInput.get())

button = tkinter.Button(screen,text="search",command=search)
frame = HtmlFrame(screen)
urlInput.grid(row=0,column=0,columnspan=2)
button.grid(row=1,column=0)
frame.grid(row=2,column=0)
screen.mainloop()

This is for anyone who wants to know how I solved it

user_182713960

Flask has a tool called render template, I use it for my website and it's not hard to implement either.... here is an example:

    from flask import Flask
    from flask import render_template

    app = Flask(__name__)
    #sets app route and renders file
    @app.route('/')
    def index():
      return render_template('index.html')
    if __name__ == "__main__":
      app.run(host='0.0.0.0', port="any port number here", debug=True)
    #debug just refreshes the main file (app.py or something.py) when a change is made

I suggest you also check out the docs on Flask to get a full understanding of it, I really hope this answers your question https://flask.palletsprojects.com/en/2.0.x/

user_152048240
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