Implicit conversion from float (number) to int loses precision

user_18183907 0
Viewed 6806

i used to use this formula before php 8.1

<?php
$number = 0;
echo log10(abs($number)) / 3 | 0;

echo PHP_EOL;

$number = 100;
echo log10(abs($number)) / 3 | 0;

echo PHP_EOL;
    
$number = 1100;
echo log10(abs($number)) / 3 | 0;

echo PHP_EOL;
    
$number = 10000000;
echo log10(abs($number)) / 3 | 0;
?>

and it worked fine but now i keep getting these errors from them after upgrading

Deprecated: Implicit conversion from float -INF to int loses precision

Deprecated: Implicit conversion from float 0.6666666666666666 to int loses precision

Deprecated: Implicit conversion from float 1.0137975617194084 to int loses precision

Deprecated: Implicit conversion from float 2.3333333333333335 to int loses precision

and i can not find or understand why it is happening now from the 8.1 docs

php
2 Answers

You're getting an implicit conversion to integer when you perform the bitwise OR operation via the | operator. It's an... odd... way to convert to integer. To avoid the warning, just explicitly convert instead.

Implicit:

echo log10(abs($number)) / 3 | 0;

Explicit via function:

echo intval(log10(abs($number)) / 3);

Or via cast:

echo (int) (log10(abs($number)) / 3);
user_4530020 
// Implicit variant
$number= "2";
$calc = 2 + $number;

// Cast variant
$number = "2";
$calc= 2 + (int) $number;

// Explicit variant
$number = "2";
$calc = 2 + intval($number);

// Everything is good variant ^^
$number = 2;
$calc = 2 + $number;
user_152224090
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