How do I remove the last character from a string in R only if it is a letter?

user_12239069 0
Viewed 42

I have a column with the values such as this:

Products
54632
54782L
5847-46x
7782M

I want to create a new column with the same values as the original but I want to remove the last character only if its a Letter so the table would look like this

Edited Products
54632
54782
5847-46
7782

Thank you

r regex
2 Answers

We could use str_replace_all with regular expression `[A-Za-z]$ .... matches letter at the end

library(dplyr)
library(stringr)

df %>% 
  mutate(Edited_Products = str_replace_all(Products, '[A-Za-z]$', ''))

  Edited_Products
1    54632
2    54782
3  5847-46
4     7782

data:

df <- structure(list(Products = c("54632", "54782L", "5847-46x", "7782M"
)), class = "data.frame", row.names = c(NA, -4L))
user_133216470

Use sub with the regex [A-Z]$ while ignoring case

df$Edited_Products <- sub('[A-Z]$', '', df$Products, ignore.case = TRUE)
df
  Products Edited_Products
1    54632           54632
2   54782L           54782
3 5847-46x         5847-46
4    7782M            7782
user_83802720
Related