Use success value of `if let` in SwiftUI 3

user_2458437 0
Viewed 59

I have this check in SwiftUI

 if tasks.first(where: { task in
            return isDone(task)
        }) != nil {
            let task = tasks.first(where: { task in
                    return isDone(task) 
                }
            )

I'm wondering if there's a way in SwiftUI 3 to use task from the check, instead of having to redefine it in the success block?

I've tried replacing the first line with if let task = tasks.first .... but it returns a Bool, which makes sense.

Not really sure what this is called so don't know what else to research.

Thank you!

swiftui swift5 xcode
1 Answers

I assume you wanted something like this (simplified):

struct Task {
    var isDone: Bool {
        true
    }
    var name = "test"
}
func foo() {
    let tasks = [Task(), Task()]

    // just don't use `!= nil` converting it to Bool
    if let task = tasks.first(where: { $0.isDone }) {
        print(task.name)
    }
}
user_122990300
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