Don't ask why I'm learning Rust using linked lists. I want to mutably iterate down a recursive structure of Option<Rc<RefCell<Node>>> while keeping the ability to swap out nodes and unwrap them. I have a singly-linked list type with a tail pointer to the last node.
pub struct List<T> {
maybe_head: Option<Rc<RefCell<Node<T>>>>,
maybe_tail: Option<Rc<RefCell<Node<T>>>>,
length: usize,
}
struct Node<T> {
value: T,
maybe_next: Option<Rc<RefCell<Node<T>>>>,
}
Let's say we have a constructor and an append function:
impl<T> List<T> {
pub fn new() -> Self {
List {
maybe_head: None,
maybe_tail: None,
length: 0,
}
}
pub fn put_first(&mut self, t: T) -> &mut Self {
let new_node_rc = Rc::new(RefCell::new(Node {
value: t,
maybe_next: mem::replace(&mut self.maybe_head, None),
}));
match self.length == 0 {
true => {
let new_node_rc_clone = new_node_rc.clone();
self.maybe_head = Some(new_node_rc);
self.maybe_tail = Some(new_node_rc_clone);
},
false => {
self.maybe_head = Some(new_node_rc);
},
}
self.length += 1;
self
}
}
I want to remove and return the final node by moving the tail pointer to its predecessor, then returning the old tail. After iterating down the list using RefCell::borrow() and Rc::clone(), the first version of remove_last() below panics when trying to unwrap the tail's Rc. How do I iterate down this recursive structure without incrementing each node's strongcount?
PANICKING VERSION
pub fn remove_last(&mut self) -> Option<T> {
let mut opt: Option<Rc<RefCell<Node<T>>>>;
if let Some(rc) = &self.maybe_head {
opt = Some(Rc::clone(rc))
} else {
return None;
};
let mut rc: Rc<RefCell<Node<T>>>;
let mut countdown_to_penultimate: i32 = self.length as i32 - 2;
loop {
rc = match opt {
None => panic!(),
Some(ref wrapped_rc) => Rc::clone(wrapped_rc),
};
match RefCell::borrow(&rc).maybe_next {
Some(ref next_rc) => {
if countdown_to_penultimate == 0 {
self.maybe_tail = Some(Rc::clone(x));
}
opt = Some(Rc::clone(next_rc));
countdown_to_penultimate -= 1;
},
None => {
let grab_tail = match Rc::try_unwrap(opt.take().unwrap()) {
Ok(something) => {
return Some(something.into_inner().value);
}
Err(_) => panic!(),
};
},
}
}
If all I do during iteration is move the tail pointer and enclose the iteration code in a {...} block to drop cloned references, I can then safely swap out and return the old tail, but this is obviously unsatisfying.
UNSATISFYING WORKING VERSION
pub fn remove_last(&mut self) -> Option<T> {
{let mut opt: Option<Rc<RefCell<Node<T>>>>;
if let Some(rc) = &self.maybe_head {
opt = Some(Rc::clone(rc))
} else {
return None;
};
let mut rc: Rc<RefCell<Node<T>>>;
let mut countdown_to_penultimate: i32 = self.length as i32 - 2;
loop {
rc = match opt {
None => panic!(),
Some(ref wrapped_rc) => Rc::clone(wrapped_rc),
};
match RefCell::borrow(&rc).maybe_next {
Some(ref next_rc) => {
if countdown_to_penultimate == 0 {
self.maybe_tail = Some(Rc::clone(&rc));
}
opt = Some(Rc::clone(next_rc));
countdown_to_penultimate -= 1;
},
None => {
break;
},
}
}}
match self.maybe_tail {
None => panic!(),
Some(ref rc) => {
let tail = mem::replace(&mut RefCell::borrow_mut(rc).maybe_next, None);
return Some(Rc::try_unwrap(tail.unwrap()).ok().unwrap().into_inner().value);
}
};
}