I tried this code:
auto p = new int (*)[10];
but I got error messeage:
test.cc:8:21: error: expected expression
auto p = new int (*)[10];
^
1 error generated.
I changed my code:
typedef int array[10];
auto p = new array *;
And then everything goes well. Why is this?
For details I refer you to https://en.cppreference.com/w/cpp/language/new.
Syntax for new without initializer is either
new (type)
or
new type
In the second case type may not contain parenthesis. This is also demonstrated in the above linked page:
new int(*[10])(); // error: parsed as (new int) (*[10]) () new (int (*[10])()); // okay: allocates an array of 10 pointers to functions
For your case that means:
auto p = new int (*)[10]; // error: parsed as (new int) ((*)[10])
auto p = new ( int (*)[10] ); // ok
When you use the alias, you can write
auto p = new array *;
because here type does not contain parenthesis.