Curry generic function with Ramda and Typescript

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I have a generic function:

function hello<T>(n: number, s: string, thing: T): Array<T> {
  return [thing]
}

const result = hello(1, 'string arg', 'generic arg')

result has type string[] which is expected.

However if I curry it:

function hello<T>(n: number, s: string, thing: T): Array<T> {
  return [thing]
}

const fun1 = curry(hello)(1, 'string arg')

const result = fun1('generic arg')

result now has type unknown[].

How can I curry a generic function in Ramda whilst maintaining the type? I'm using Ramda 0.27.1

ramda.js typescript currying generics
1 Answers

The signature of R.curry with 3 parameters is:

curry<T1, T2, T3, TResult>(fn: (a: T1, b: T2, c: T3) => TResult): CurriedFunction3<T1, T2, T3, TResult>;

As you can see, you'll need to manually type the curried function (codesandbox):

function hello<T>(n: number, s: string, thing: T): Array<T> {
  return [thing];
}

const fun1 = curry<number, string, string, string[]>(hello)(1, 'string arg');

const result = fun1('generic arg');

console.log(result);
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