I am using GetX in my project. Lets suppose I have two screens. Each screen have a button. The controller of first screen have observable list of objects. When a button in first screen is pressed, one of the object list is sent to second screen.
In second screen user changes the value of the data received and when save button is pressed, I want to update the observable list in first screen as well.
I know I can use Get.back() to send updated data back to first screen. I could do following in second screen
Get.back(result: [
{"updatedObject": listDetails}
]);
And in first screen I could do
Get.to(() => SecondScreen(), arguments: [
{"list": listDetails[index]}
]).then((result) {
// result[0]["updatedObject"] // use this to update list observable
});
My Question.
Can I update list in first screen without navigating back to first screen when Save button is pressed.
I am pretty new with GetX and i am trying to learn it. Thanks