Using 'REPLACE' within 'COND' statement

user_8104381 0
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I am trying to replace a substring in a string based on certain condtions using COND #. But not sure where to incorporate REPLACE in the syntax.

Normal code:

DATA(v_string) = 'My string &1 &2'.

IF v_string CA '&1'.
  REPLACE '&1' WITH 'sub1' in v_string.
ELSEIF v_string CA '&2'.
  REPLACE '&2' WITH 'sub2' in v_string.
ENDIF.

I am trying to achieve the same using ABAP 7.5 syntax.

v_string = COND #( WHEN v_string CA '&1' THEN REPLACE '&1' WITH 'sub1' in v_string
                   WHEN v_string CA '&2' THEN REPLACE '&2' WITH 'sub2' in v_string ).

What is the correct syntax to get the desired results?

abap
1 Answers

As per documentation, the THEN operand must be a a general expression position, which is defined as

Reading position in which (alongside a suitable data object) a constructor expression, a table expression, a calculation expression, a built-in function, a functional method, or a method chaining can also be specified.

That means REPLACE is not available, but you can use built-in string function replace.

v_string = COND #( 
  WHEN contains( val = v_string sub = '&1' ) 
    THEN replace( val = v_string sub = '&1' with = 'sub1' occ = 1 )
  WHEN contains( val = v_string sub = '&2' ) 
    THEN replace( val = v_string sub = '&2' with = 'sub2' occ = 1 )
).
user_68743590
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