checking symbol equality in defmacro (clojure)

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This returns false.

(defmacro scratch [pattern]
  `(= 'b (first ~pattern)))

(scratch '(b))

However, the output of the following is b.

(defmacro scratch2 [pattern]
  `(first ~pattern))

(scratch2 '(b))

How do I setup the first macro to return true?

clojure symbols macros
1 Answers

that is happening, because the 'b that you introduce in macro is namespaced:

example:

user> (defmacro nsmac []
        `(namespace 'b))

user> (nsmac)
;;=> "user"

while the value you pass isn't:

user> (namespace (first '(b)))
;;=> nil

so, you can pass the namespaced symbol to a macro, like this:

user> (scratch '(user/b)) 
;;=> true

or you can fix you macro to use unnamespaced symbol (known trick with qoute-unquote):

(defmacro scratch [pattern]
  `(= '~'b (first ~pattern)))

user> (scratch '(b)) 
;;=> true

but what you really want, is to check this one in compile-time, because this macro you have is better as a plain function, since it doesn't employ any macro-related goodness.

It could look like this:

(defmacro scratch [pattern]
  (= 'b (first pattern)))

(scratch (b))
;;=> true

something about namespacing can be found in this article

user_54005480
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