Hi guys can someone help me with this
$input_lines= array("asdf","fdas", "asds", "d fm", "dfaa", "aaaa", "aabb", "aaabb");
preg_grep('/a{2}/', explode("\n", $input_lines));
Now this returns every string that has atleast 2 a BUT what I want is for it to return every string that has more than 2 character, whatever that character is whether a, b or s This is the output I want to achieve
asds
dfaa
aabb
aaabb
@Emmanuel, in this solution have a two key function unpack which help we can get the ASCII of each character from give string(that return as array) and array_unique using this we can convert to unique array and then check with it's original array count if it's less than original array than there is repeat character in it. [Note: this solution can also work with mix string i.e. characters and numbers e.g 'asw11d']
<?php
$input_lines= array("asdf","fdas", "asds", "d fm", "dfaa", "aaaa", "aabb", "aaabb");
for($i=0;$i<count($input_lines);$i++)
{
$ChrFilter= unpack("C*",$input_lines[$i]);
if(count(array_unique($ChrFilter))<count($ChrFilter))
{
echo $input_lines[$i];
echo '<br>';
}
}
?>
Out Put:
asds
dfaa
aaaa
aabb
aaabb
You can use
$input_lines= array("asdf","fdas", "asds", "d fm", "dfaa", "aaaa", "aabb", "aaabb");
print_r(preg_grep('/(\p{L}).*\1/', $input_lines));
Note that '/(\p{L}).*\1/' regex matches any letter (capturing it into Group 1 with (\p{L})) and then matches any zero or more chars other than line break chars as many as possible (with .*) and then matches the same char as captured in Group 1. See the regex demo.
Output:
Array
(
[2] => asds
[4] => dfaa
[5] => aaaa
[6] => aabb
[7] => aaabb
)
See the PHP demo.
Without using a regex, you can do that:
$arr = ["asdf","fdas", "asds", "d fm", "dfaa", "aaaa", "aabb", "aaabb"];
$res = array_filter($arr, fn($s) => strlen($s) > strlen(count_chars($s, 3)));