How to pass SwiftUI View as function parameter?

Question

I want to show SwiftUI Views as subview of a UIViewController. These views must implement a protocol.

I have this:

protocol ContentViewProtocol : View
{
    var values: [CGFloat] { get }
}

...

import SwiftUI

struct SearchContentView : ContentViewProtocol
{
    var values: [CGFloat] = [0.5, 0.7]

    var body: some View
    {
        VStack
        {
            ...
        }
    }
}

...

func showContent(view: ContentViewProtocol) <=== ERROR
{
    var child = UIHostingController(rootView: view) <=== SAME ERROR

    ...
}

I get the following error: Protocol 'ContentViewProtocol' can only be used as a generic constraint because it has Self or associated type requirements

I get the same error when using a plain View as function parameter type (so with func showContent(view: View)).

How can I prevent this?

user_5133585 · Answer

You can do what the error says, and use ContentViewProtocol as a generic constraint. Make showContent generic:

func showContent(view: V)
{
    let child = UIHostingController(rootView: view)
    ...
}

How to pass SwiftUI View as function parameter?

1 Answers