How to get the tail of `$^` in Makefile

user_6708910 0
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I have the following rule in a Makefile

%/collapsed_flow_profile.png: \
code/piv/plot_collapsed_flow_profiles.R \
%/experiment2/averaged_flow_profile.csv \
%/experiment3/averaged_flow_profile.csv \
%/experiment4/averaged_flow_profile.csv \
%/experiment6/averaged_flow_profile.csv \
%/experiment7/averaged_flow_profile.csv
    code/piv/plot_collapsed_flow_profiles.R \
$*/collapsed_flow_profile.png \
$*/experiment2/averaged_flow_profile.csv \
$*/experiment3/averaged_flow_profile.csv \
$*/experiment4/averaged_flow_profile.csv \
$*/experiment6/averaged_flow_profile.csv \
$*/experiment7/averaged_flow_profile.csv

As you can see, I'm passing all the dependencies except the first one as an argument to the code used in the recipe. Since $^ automatic variable contains all the dependencies, it is possible to remove the first dependency from $^ and pass it to the code as an argument?

gnu-make makefile
1 Answers

There are $(firstword a b c) -> a and $(filter-out ...) and $(wordlist s,e,text) functions for transforming text. Combining them might be able to do what you want. The excellent documentation has the details.

PS: What happened to experiment 5? Outlier? Does not fit expectations? :-)

user_6486580
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