Fastest way to create a square nxn matrix from 1d array in numpy

user_17236990 0
Viewed 280

Suppose the following numpy array:

arr = np.array([0, 1, 2, 3, 4]) # can be any array

I want to know the fastest way to generate the following operation:

n = arr.shape[0]
result = np.tile(arr, (n, 1)) - arr.reshape((-1, 1))
print(result):

array([[ 0,  1,  2,  3,  4],
       [-1,  0,  1,  2,  3],
       [-2, -1,  0,  1,  2],
       [-3, -2, -1,  0,  1],
       [-4, -3, -2, -1,  0]])

(1) How to efficiently create matrix "result" (because n >> 0 can be very large) ?

(2) Does this matrix have a particular name ?

scipy numpy arrays python
1 Answers

This is a bit faster:

result = arr-arr[:,None]

cursory benchmarks, nothing scientific. (timeit 100 times with arr):

          5 items (arr) 100 times   10,000 items (np.arange) once
OP:       0.0006383560000000066     0.7902513520000001
This one: 0.0001735200000000381     0.3640661519999999
Kelly's:  0.00027326299999996806    0.36036748900000015 (see comments)
user_52375600
Related