Ignore the first space in CSV

Try to fix the column and the index after load the file:

import pandas as pd

points = pd.read_csv('test.csv', delim_whitespace=True)

points = points.assign(Time=pd.to_datetime(df.index + ' ' + df['Time'])) \
               .reset_index(drop=True)

Output:

>>> points
                 Time  Latitude  Longitude
0 2021-09-12 23:13:00     44.63     -63.56
1 2021-09-14 23:13:00     43.78     -62.00
2 2021-09-16 23:14:00     44.83     -54.60

Your data is in 2 different kind of formats:

• your headerrow has a single space between 'Latitude' and 'Longitude'.
• the "data" rows look to be separated by multiple spaces.

You can either edit your data and add a second space between lat & long or trick it by supplying the column headers separately:

Create file:

with open("test.csv","w") as f:
    f.write("""Time              Latitude Longitude
2021-09-12 23:13    44.63     -63.56
2021-09-14 23:13    43.78     -62
2021-09-16 23:14    44.83     -54.6""")

Parse file:

import pandas as pd

# ignore files headers, supply own, use multiple spaces as seperator
df = pd.read_csv("test.csv", delimiter = "   ", 
                 header=0, names = ["Time","Latitude","Longitude"])

print (df)

Output:

               Time  Latitude  Longitude
0  2021-09-12 23:13     44.63     -63.56
1  2021-09-14 23:13     43.78     -62.00
2  2021-09-16 23:14     44.83     -54.60

What you have shown is not a csv file. Full stop. Pandas read_csv is indeed versatile enough to possibly find workaround allowing to process it. But it is actually a fixed width fields file and should be read with pd.read_fwf:

pd.read_fwf(file_name, [(0,16), (16,26), (26, 40)])

directly gives:

               Time  Latitude  Longitude
0  2021-09-12 23:13     44.63     -63.56
1  2021-09-14 23:13     43.78     -62.00
2  2021-09-16 23:14     44.83     -54.60

From your edit, you only want to tell read_csv to consider the first white space as a non delimiter character. I know no simple way to do that. The hard way is to read the file, replace the first space in each and every line with a different character. Then you submit that changed file to read_csv with a custom converter for the first column to change the special character back to a space:

with open('test.csv') as fdin, open('test2.csv', 'w') as fdout):
    fdout.write(next(fdin)    # do not process the header line
    for line in fdin:
        fdout.write(line.replace(' ', '_', 1)

df = pd.read_csv('test2.csv', delim_whitespace=True,
                 converters = {'Time': lambda x: x.replace('_', ' ')})

It gives too:

               Time  Latitude  Longitude
0  2021-09-12 23:13     44.63     -63.56
1  2021-09-14 23:13     43.78     -62.00
2  2021-09-16 23:14     44.83     -54.60

Ideally you should be parsing the first two parts as a datetime. By using a space as a delimiter, it would imply the header has three columns. The space after the date though is being seen as an extra column.

A workaround is to skip the header entirely and supply your own column names. The parse_dates parameter can be used to tell Pandas to parse the first two columns as a single combined datetime object.

For example:

import pandas as pd

points = pd.read_csv("test.csv", delimiter=" ", 
    skipinitialspace=True, skiprows=1, index_col=None, 
    parse_dates=[[0, 1]], names=["Date", "Time", "Latitude", "Longitude"])

print(points)

Should give you the following dataframe:

            Date_Time  Latitude  Longitude
0 2021-09-12 23:13:00     44.63     -63.56
1 2021-09-14 23:13:00     43.78     -62.00
2 2021-09-16 23:14:00     44.83     -54.60

How about pd.read_csv(..., skipinitialspace=True)^1?

skipinitialspacebool, default False

Skip spaces after delimiter.

The Python csv module also has a skip-initial-space option^2 (not sure if Pandas made up its own, or wraps this):

Dialect.skipinitialspace

When True, whitespace immediately following the delimiter is ignored. The default is False.

Even though it explicitly states "following the delimiter", it does the sensible thing and ignores leading whitespace in any column/cell.

Given the following input.csv, which has a leading space in all of columns 1 and 2:

 H1  H2
 A  1
 B  2
 C  3

When I run this:

import csv

with open('input.csv', newline='') as f:
    reader = csv.reader(f, delimiter=' ', skipinitialspace=True)
    for row in reader:
        print(row)

I get:

['H1', 'H2']
['A', '1']
['B', '2']
['C', '3']

Even if Pandas doesn't support this, at least you could use this as a preliminary transform and feed into Pandas.